What's wrong with the code......

Question

I'm trying to add two times and display them.
https://code.sololearn.com/cPGFU1P0f9V5

Answer 1

Md Ibrahim (West Bengal, India) , compare it with your code and if you don't understand anything, ask for clarification..

few points I am mentioning:

after cout and << ; you cannot call void function. void function doesn't return any thing and cout << requires something to print... so moving function call to new line without cout.

in sum function, you were returning t which is time type...so changed it's return type from int to time in definition... within class declaration of this function, changed type to time instead of void.

in function of sum,

time t,r.hour=0; is incorrect...
r.hour is of time other than time.

int a,b means a and b both are of int type. so, time t and r.hour=0 should be seperated by semicolon

Answer 2

Md Ibrahim (West Bengal, India) below is working code:

#include<iostream>
using namespace std;

class Time
{
int hours,minutes;
public:
void input(int h, int m)
{
hours=h;
minutes=m;
}
void display()
{
cout<<hours<<" hours and "<<minutes<<"minutes"<<endl;

}
Time sum(Time);//declarations with object arguments
};

Time Time::sum(Time t1)
{
Time r;
r.minutes=0,r.hours=0;
r.minutes=minutes+t1.minutes;
r.hours=r.minutes/60;
r.minutes=r.minutes%60;
r.hours=hours+t1.hours+r.hours;
return r;
}

//main function
int main()
{
Time a1;

Time a2;
Time a3;
a1.input(2,45);
a2.input(3,30);

a3=a1.sum(a2);//T3=T1+T2;

cout<<"T1= ";
a1.display();
cout<<"T2= ";
a2.display();
cout<<"T3= ";
a3.display();

}

Answer 3

Ketan Lalcheta Thank you so much for your valuable time...It's working.

Answer 4

Ipang. Ketan [#Be Happy 😸] plz help