Java question

Question

Why is
Integer.min_value - integer.max_value /2= 0?

Answer 1

Try this

System.out.print((double)(Integer.MIN_VALUE-Integer.MAX_VALUE)/2);

Answer 2

Simply primitive datatypes will have weird behavior when their values cross the limits.

Answer 3

I assume it's because crossed the integer minimum size limit.
Smallest possible primitive integer in Java is -2^31, and biggest possible primitive integer in Java is 2^31-1.
-2^31 - 2^31-1 = -2^32-1

-2^32-1 < -2^31

Answer 4

~ swim ~ yes that's right 👍,I thought he might of been looking for somthing diffrent becuase 0 is the correct answer... who knows 😅

Answer 5

~ swim ~ I got the value 0.5 but was converted to int 0 so I needed to cast it back to double? also due to order of operation / has higher precedence then -