Can i square root the result of a function?

Question

import math

def c(a, b):
return(a**2+b**2)

print (math.sqrt(c))

Answer 1

You could make it part of the function, e.g.
def sqrt_of_sum_of_squares(a, b):
return (a*a + b*b)**.5
print(sqrt_of_sum_of_squares(3, 4))

Answer 2

c is the function itself, here is how you should do it:
a = int(input())
b = int(input())
print(math.sqrt(c(a, b)))

Answer 3

Jacob Ferrari-Shaikh Thanks! You can also use the pow() function to get a square root, i.e. return pow(a*a + b*b, .5) 🙂

Answer 4

Nevermind that didn't work! I don't get an output

Answer 5

Jacob Ferrari-Shaikh show me your whole code, it should be working. Also, try it without input, directly give a and b values, for example:
print(math.sqrt(c(2, 5)))
Sololearn input is not very good, maybe that's where the problem is.

Answer 6

What would I do if I wanted to square a and b though and then square root the result?

Answer 7

Sorry square a and b and then add them and then square root the result

Answer 8

def c(a, b):
return (a**2+b**2)
print(c(2, 4)**(1/2))

Answer 9

If you want the function c to give the square root of the sum of the squares directly, you could introduce an intermediate variable in the code and set it up like this:

https://code.sololearn.com/cVTbRYOtILzd/?ref=app

Answer 10

David Ashton awesome that's what I was looking for! Didn't know **.5 worked as a square root