I=j=k=1; ++i || ++j && ++k why does it increment only, and not j and k

Question

&& has higher precedence, shud be evaluated before ||

Answer 1

Thanx for ur reply.
But sorry i m still confused.
Just as u have written in
++I || ( ++j && ++k )

why && is not evaluated
why bracket is not solved first

Kindly explain.
Thanx and regards.

Answer 2

Ok..
Got it.
Thanx a lot.

Answer 3

Short circuit is ok.
It will come into picture when we have something like a||b and a is true, b need not be solved.
But here my question is about precedence.

Why && is not solved before ||

Please reply.
Thanx.