How to compare all list items and arrange them in ascending order?

Question

For example:
I have list
list = [2,6,8,4,3,2,9,15,0]
I want to compare all the elements and arrange them in ascending order
And I should get in input
list = [0, 2, 2, 3, 4, 6, 8, 9, 15]

Answer 1

Sorting in python can be done in 2 ways:

# please dont use the name list as a variable or object name. This can lead to unexpected behaviour !!!

lst = [2,6,8,4,3,2,9,15,0] # original list
print(lst)

# sorting in place - changes original list in defined order
lst.sort()
print(lst)
# output: [0, 2, 2, 3, 4, 6, 8, 9, 15]

# sorting not in place - list keeps in original order, new list with sorted items will be created
list = [2,6,8,4,3,2,9,15,0]
res = sorted(lst)
print(res)
# output : [0, 2, 2, 3, 4, 6, 8, 9, 15]

Both versions can have an optional key argument to do user defined sorting. Therefor a lambda function is used.

Answer 2

It is called sorting.
https://www.sololearn.com/learn/774/?ref=app
You can learn here about the different sorting algorithms.