HELP WITH EASY HOMEWORK CODE - [Dynamic Memory Allocation]

Question

Hello, I am taking C++ beginner class and I can't get to do this.

The instruction is:

1. cin >> size of array
2. cin >> number (in array)
3. cout << "Number of values grater than the average is " <<
( HINT : int* list = new list[size] )

And the answer should be this.

Enter array size: 3
Enter number: 1
Enter number: 5
Enter number: 7
The number of values greater than the average is 2

Please, some help :(( I don't know how to get the average or how to make the "enter a number" repeat when using dynamic memory allocation.

Answer 1

Ok, thank you very much for your help - swim - !
I will keep working on that!

Answer 2

I'm sorry, I know what you mean. Here I tried to do this code:

#include <iostream>
using namespace std;

void aboveAvg();

int main()
{
int size, i;
double sum = 0;
double Avg;

cout << "Enter array number: ";
cin >> size;

int* list = new int[size];

for (i = 0; i < size; ++i)
{
cout << i + 1 << "Enter a number: ";
cin >> list[i];
sum += list[i];
}
Avg = sum / size;

cout << "The numbers greater than average are: " << aboveAvg() << endl;

return 0;
}

void aboveAvg(double Avg, int *list){

if (*list > Avg)
{
cout << *list << " " << endl;
}

}

------
I only have one error which says " no operator << matches this operands" before aboveAvg << endl;

I need some guidance with that. Also, if someone could check if my void code is correct I would really appreciate it, I still find it difficult to understand how to call array and its elements into a void function.