Can we define what happens when operators are used along with Objects in Java?

Question

I just wondered if we can tell operators like -, +, *, ^ and / when they are use with objects. Maybe even %.

Expectation :
class obj {
--> whatever is required to start defining a
behaviour, say subtraction
Return obj1.val - (obj2.val*2);
}
obj A = new obj(); A.setVal(12);
obj B = new obj(); B.setVal(3);

S.o.print(A-B); //out-> 6

*** Please, there is no need to align your answers along my expectation. I would be just as eager to know what else can be done.

Thank You

Answer 1

Yeah i heard about that. But my focus was more around the fact that String in not a DataType! It is an Object.

When we perform an action like:
"Value 1" + 1025;
Java interprets it as something similar to:
new StringBuilder("Value 1").concate(1025).toString();

So, can we define such a behaviour for other objects?

Answer 2

Haha, nice zemiak. Well, then we have to use methods only!

Answer 3

~ swim ~ , ok i get it.

Answer 4

Thanks everyone

Answer 5

// this is joke

public class Obj {
int val;
int $ (Obj o) {return this.val + o.val;}; // + sum
int __ (Obj o) {return this.val - o.val;}; // - subtraction

public static void main(String[] args) {
Obj a=new Obj(), b=new Obj();
a.val = 30;
b.val = 20;
System.out.println( (a). $ (b) ); // 50
System.out.println( (a). __ (b) ); // 10
}
}