Who can help me? I want to write if(b==0 && c==0) { printf("x=0"); } but when I write this my program don't work!

Question

https://code.sololearn.com/c5muJyJh8JyI/?ref=app

Answer 1

There is mistake in a*x*x=0
Because this is rule in c that only one variable should be on left of the assignment operator(=).
So a*x*x=0 is not possible because it is invalid

Answer 2

Try to use double in place of float. Comparison of float value against a literal (such as 0) usually fails due to the fact that the literal 0 is by default a double type value. Difference of precision accuracy between float and double is the cause, most of the times.

Answer 3

Erik Margaryan
To be honest I don't think I'm understanding your code. Maybe it's because I'm no good in math. Can you tell me what exactly is this code doing? maybe I can help further if I can understand it (hope so).

Answer 4

ax²+bx+c=0
a,b,c are constant.
When a=0 => x = -c/b and b ≠ 0,
When b=0 => ax²+c=0, x²=-c/a, x1, x2 = ±√(-c)/a => c or a have to less than 0 and a ≠ 0.
When c=0 => ax² +bx=0, x(ax+b)=0 => x1=0 and x2=(-b)/a and a≠0.
Discriminate means 'D' symbol..
When a≠0 and b≠0 and c≠0 then
D=b²+4ac,
When D<0 then x=ø,
When D>0 then
X1, X2 = (-b ± √D)/2a
This is "Square Equation". You can search Square Equation by Google for understand better!
Now I want to write when b=0 and c=0 => ax² = 0 => x=0. But my program don't work!

Answer 5

Thanks Erik Margaryan ,
I think I should've learn that square equation first before I commented XD

I hope someone knowledgeable sees your post and help you with it.

Good luck! 👍

Answer 6

But who can answer me which line to write that? if(b==0 && c==0) {
printf("x=0");
}

Answer 7

I write that different lines and output is:
X=0
X_1=.....
X_2=....
.....
But I need only x=0.

Answer 8

Thanks!! I hope too.

Answer 9

Sees my program again! I already find my error.🥳

Answer 10

هبص

Answer 11

https://code.sololearn.com/cK8gWDxC2Acp/?ref=app

Answer 12

See of my program more improve version!👏