+ 1

how to call a overloaded operator in c++?

how to use original purpose of operator instead of user defined one

8th Feb 2017, 5:11 PM
MARRI ESWAR REDDY
MARRI ESWAR REDDY - avatar
1 Odpowiedź
+ 1
similar to normal function call, return_type operator()(parameter_list)
12th Feb 2017, 12:41 AM
Supriya S M
Supriya S M - avatar