Error

Question

What’s wrong with this code in c language
#include <conio.h>
#include <stdio.h>
int main()
{
int i,n,j;
printf("enter a number");
scanf("%d",&n);
for (i=0;i<n;i++)
{
for(j=0;j<n;j++)
if(i==0 || j==0 || i==n-1 || j==n-1 || j+i==n-1)
printf("*");
else
printf(" ");

return 0;
}

It said error:unpaired curly brackets.

Answer 1

Saba I already fixed your previous code have an look here
https://code.sololearn.com/cdVy8U02Cpr5/?ref=app

it's same as that problem

int main()
{
// n denotes size which should be odd
int i, j, n;
scanf("%d", &n);
// Function calling
//pattern(n);
for (int i = 0; i < n; i++) {
// Loop denoting columns
for (int j = 0; j < n; j++) {
// Checking boundary conditions and main
// diagonal and secondary diagonal conditions
if (i == 0 || j == 0 || i == j || i == n - 1 || j == n - 1 || i + j == n - 1)
printf("*");
else
printf(" ");
}
printf("\n");
}

return 0;
}

Answer 2

after for loop you opend a curly bracket but you didnt close it
by the way your program doesnt need conio.h header file

Answer 3

In your code, there were 2open braces & 1 closed brace
Add 1closed curly brace at the end