+ 1

What does c++ code do ??

I've seen this code before but never ask me what it really does. i just know it's a bitwise operator but what it does behind de scene, is in fact my question?, i hope someone can explain me. int main() { int integer = 5; if (integer & 0x3) { cout << "surprise"; } return 0; }

1st Dec 2019, 7:16 AM
elkevindeveloper
elkevindeveloper - avatar
4 odpowiedzi
+ 10
In this code you have used an hexadecimal number 0x03 which is 3 in decimal. 0x is representing the hexadecimal digit if you do 0x10 then the digit will be 16 in decimal And integer value is defined as 5 so 5&3 two zero integer will return true so output is come as "surprise" If you do 0x00 then the and operation failed as any value which generate 0 will become make condition false
1st Dec 2019, 7:28 AM
GAWEN STEASY
GAWEN STEASY - avatar
+ 7
Dec | Binary | 5 | 0101 | 3 | 0011 | --------------------- & 1 | 0001 | In C/C++ any non zero integral value is considered true when the value is treated and/or used as logical expression (as if it were a boolean value), or as part of a logical expression. From the bitwise AND operation shown above, we can see that since `5 & 3` yields 1 (which is considered true), that's why the `if` block was executed. Had the operation yield zero (false logically), the `if` block would not have been executed. There's a bitwise operators intro available in the Learn section. Pay a visit there to get a better understanding 👍 https://www.sololearn.com/learn/4070/?ref=app
1st Dec 2019, 10:19 AM
Ipang
+ 3
The "&" is called the bitwise AND operator. Also a number starting from 0x is a hexadecimal number. So now convert both the numbers to binary and do & operation on them. This code will give you "not surprised" because the & of 5 and 8 will give 0. So the if condition fails and the else is executed. int integer = 5; if (integer & 0x8) { cout << "surprise"; } else cout << "not surprised";
1st Dec 2019, 8:25 AM
Avinesh
Avinesh - avatar
+ 2
No one explained what the & does "behind the scene" yet, apart from saying it's the bitwise and operator. The & operator looks through the bits of 2 numbers and generates a new number. If both bits are 1, the resulting bit is also 1. Any other combination is a 0. Example: 5 00000101 & 3 00000011 = 1 00000001 91 01011011 & 36 00100100 = 00 00000000 It is often used as a bitmask: https://en.m.wikipedia.org/wiki/Mask_(computing)
1st Dec 2019, 9:21 AM
Dennis
Dennis - avatar