why the resulte is equal to 2 //Like it if u love it

Question

#include <iostream>
using namespace std;

int main() {
int i=true;
int j=false;
if (i!=j){
cout << (++i);
}else{
cout << (i);
}
return 0;
}

Answer 1

because i is equal to 1 and j is equal to 0
i is diffident to j
then i is incremented by 1

Answer 2

The result is two because you are specifying the variable types as 'int'. Because you are doing that, i = 1, and j = 0. (1 being the integer "equivalent" of true, and 0 for false.) Then, you test if i is not equal to j, which it is, so then you output 2. You are outputting 2 because you are incrementing i before the variable name. (++i = 2) If you were to type i++, you would be outputting 1.