What is speicial with int c=9?

Question

Why c=9 behave diferently fro example c=2 in cout?
https://code.sololearn.com/c3CBrMQA6X9L/?ref=app

Answer 1

it does exactly the same. an increase of two.
it doesn’t print 911 also not 9 1 1
no it prints 9 11
which is an increase of 2
same as 2 4 (also increase of 2)

if you don’t know why:
c++ prints the number first and then increases it by 1
so
c = 9;
cout << c++ (prints c first which is 9 and then increases it, so after printing it it becomes 10

if you follow that by ++c the following happens

++c increases first and then outputs

so
c = 9
cout c++ (prints 9 increases to 10)

(c is now 10)

cout ++c (increases to 11 first and then prints)

Answer 2

Nadav Vinik , I think you are a bit confused
It is same for both value 9 and 2

I have just added comments to your code to explain what is happening. Just have a look at it👇

https://code.sololearn.com/c8khAwo5QDiz/?ref=app

Answer 3

That's because of Post and Pre increment operator.
Check them out from the link below to see how they works
https://www.sololearn.com/learn/CPlusPlus/1610/

Answer 4

Look there are two types for increment
1- postfix = c++
2- prefix. = ++c

And the compiler compile from left to right then it will increase one to the variable when it find ++
For example ++c it will increase c by one and then cout it because ++ is first

Answer 5

Thanks. I should see it :(