Help me in Solving this?

Question

#include <stdio.h>

int main() {
int n, sum=0;
scanf("%d",&n);
int a[n];
for(int i=0; i<n; i++)
scanf("%d",&a[i]);
printf("\n%d",a); //What does this line output? It ha scompiled successfully
int* b=&a;
printf("\n%p",b);
for(int i=0; i<n; i++){
sum=sum+a[i];
}
printf("\nSum=%d",sum);
return 0;
}

Answer 1

"a" is a pointer type so probably it will compile since pointers are of type - unsigned long int.

But you should use the format specifier "%lu" to escape errors, if at all they occur.

Edit: It should output the address of the array. "a" always points to the address of first element in the array.