Code Coach : Convert US date to Europe

Question

I couldn't find what went wrong in my (python) code. The last test case failed, but all the other 4 have passed. I can't see the test case, so i can't figure out the input and see what the problem is.
Wondering if anybody had this problem.
👇👇👇👇 Here is the code
===================================
in_day = input()
month={"January":"1","February":"2","March":"3","April":"4","May":"5","June":"6","July":"7","August":"8","September":"9","October":"10","November":"11","December":"12"}
#separate month, date and year
in_day = in_day.replace("/", " ")
in_day = in_day.replace(",", "")
word_list = in_day.split()

if word_list[0].isalpha():
mm = month[word_list[0]]
else:
mm = word_list[0]
dd = word_list[1]
yyyy = word_list[2]
out = "{d}/{m}/{y}".format(d=dd ,m =mm ,y=yyyy)
print(out)
===================================

Answer 1

Comma needs to vanish not become a space as it is followed by a space.

Answer 2

Solved! Thanks to John Wells and TheWh¡teCat.

Answer 3

Besufkad Tsegaye , I think you wrote wrong the key for August => you wrote "Augest". Change it and try again 🐱

Answer 4

import calendar as c
s=str(input())
l=[]
for i in range(1,13):
l.append(c.month_name[i])

if '/' in s:
v=s.split("/")
else:
v=s.replace(',',"").split(" ")

day=v[1]
year=v[2]
if v[0].isalpha():
mon=l.index(v[0])+1
else:
mon=v[0]

print(f"{day}/{mon}/{year}")

Here is my code , all test case passed.

Answer 5

May 1, 2345 does not get processed as it fails len(usdate) <= 10 and len(usdate) > 13.

Answer 6

January 10, 2020 becomes 10/01/2020 becomes 1/01/2020 as you remove the first 0 trying to get the second.

Answer 7

n = input()

if '/' in n:
n = n.split("/")
month = n[0]
date = n[1]
year = n[2]
print(f"{date}/{month}/{year}")

else:
m = ["NULL", "January", "Febuary", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
n = n.split(" ")
month = n[0]
date = n[1].split(",")[0]
year = n[2]
print(f"{date}/{m.index(month)}/{year}")

Answer 8

John Wells woooohooo finally solved, thanks a lot for helping. It's been such a nice learning experience. Looking forward to learn more 🍻

Answer 9

# ------ Date converter ------
import re
x = input()
check = re.compile(r'(\d\d|\d)?/(\d|\d\d)?/(\d{4})')
mo1 = check.findall(x)

if mo1 != []:
date_regex = re.compile(r'(\d\d|\d)?/(\d|\d\d)?/(\d{4})')
mo = date_regex.search(x)
print(f'{mo.group(2)}/{mo.group(1)}/{mo.group(3)}')
else:
name_d = re.compile(r'(\w*) (\d|\d\d),(\d{4})')
mo = name_d.search(x)
if mo.group(1) == 'January':
print(f'{mo.group(2)}/1/{mo.group(3)}')
elif mo.group(1) == 'February':
print(f'{mo.group(2)}/2/{mo.group(3)}')
elif mo.group(1) == 'March':
print(f'{mo.group(2)}/3/{mo.group(3)}')
elif mo.group(1) == 'April':
print(f'{mo.group(2)}/4/{mo.group(3)}')
elif mo.group(1) == 'May':
print(f'{mo.group(2)}/5/{mo.group(3)}')
elif mo.group(1) == 'June':
print(f'{mo.group(2)}/6/{mo.group(3)}')
elif mo.group(1) == 'July':
print(f'{mo.group(2)}/7/{mo.group(3)}')
elif mo.group(1) == 'August':
print(f'{mo.group(2)}/8/{mo.group(3)}')
elif mo.group(1) == 'September':
print(f'{mo.group(2)}/9/{mo.group(3)}')
elif mo.group(1) == 'October':
print(f'{mo.group(2)}/10/{mo.group(3)}')
elif mo.group(1) == 'November':
print(f'{mo.group(2)}/11/{mo.group(3)}')
elif mo.group(1) == 'December':
print(f'{mo.group(2)}/12/{mo.group(3)}')

Answer 10

African Nani Puji Versandi,
Bro U just copy paste my code.

Answer 11

import re

date = input()

if re.match(r"[A-Za-z]",date):

if re.match(r"January",date):
date = re.sub("January", "1", date)

elif re.match(r"February",date):
date = re.sub("February", "2",date)

elif re.match(r"March",date):
date = re.sub("March", "3",date)

elif re.match(r"April",date):
date = re.sub("April", "4",date)

elif re.match(r"May",date):
date = re.sub("May", "5",date)

elif re.match(r"June",date):
date = re.sub("June", "6",date)

elif re.match(r"Jule",date):
date = re.sub("Jule", "7",date)

elif re.match(r"August",date):
date = re.sub("August", "8",date)

elif re.match(r"September",date):
date = re.sub("September", "9",date)

elif re.match(r"October",date):
date = re.sub("October", "10",date)

elif re.match(r"November",date):
date = re.sub("November", "11",date)

elif re.match(r"December",date):
date

Answer 12

My solution od this:

import re

date = input()

if re.match(r"[A-Za-z]",date):

if re.match(r"January",date):
date = re.sub("January", "1", date)

elif re.match(r"February",date):
date = re.sub("February", "2",date)

elif re.match(r"March",date):
date = re.sub("March", "3",date)

elif re.match(r"April",date):
date = re.sub("April", "4",date)

elif re.match(r"May",date):
date = re.sub("May", "5",date)

elif re.match(r"June",date):
date = re.sub("June", "6",date)

elif re.match(r"Jule",date):
date = re.sub("Jule", "7",date)

elif re.match(r"August",date):
date = re.sub("August", "8",date)

elif re.match(r"September",date):
date = re.sub("September", "9",date)

elif re.match(r"October",date):
date = re.sub("October", "10",date)

elif re.match(r"November",date):
date = re.sub("November", "11",date)

elif re.match(r"Decembe

Answer 13

import re
date=input()
month={"January":"1","February":"2","March":"3","April":"4","May":"5","June":"6",
"July":"7","August":"8","September":"9","October":"10","November":"11","December":"12"}
date=date.replace("/"," ")
date=date.replace(","," ")
lst=date.split()
if lst[0] in month:
month_nb=month[lst[0]]
eu_date="{1}/{0}/{2}".format(month_nb,lst[1],lst[2])
print(eu_date)
else:
eu_date="{1}/{0}/{2}".format(lst[0],lst[1],lst[2])
print(eu_date)

Answer 14

Guys all the test cases were passed except the 3rd... Can someone please help me out?

date=input()
if date[2]=="/":
date=date.replace("/"," ")
date=date.split()
date[0],date[1]=date[1],date[0]
print(date[0]+"/"+date[1]+"/"+date[2])
else:
date=date.split()
date[0],date[1]=date[1],date[0]
if date[1]=="January":
date[1]="01"
elif date[1]=="February":
date[1]="02"
elif date[1]=="March":
date[1]="03"
elif date[1]=="April":
date[1]="04"
elif date[1]=="May":
date[1]="05"
elif date[1]=="June":
date[1]="06"
elif date[1]=="July":
date[1]="07"
elif date[1]=="August":
date[1]="08"
elif date[1]=="September":
date[1]="09"
elif date[1]=="October":
date[1]="10"
elif date[1]=="November":
date[1]="11"
elif date[1]=="December":
date[1]="12"
if len(date[0])>2:
print(date[0][0:2]+"/"+date[1]+"/"+date[2])
else:
print(date[0][0:1]+"/"+date[1

Answer 15

This is my code it's working well on computer terminal but in sololearn terminal it only pass two test case 🤐

date = input()
#date = "07/26/2019"

dict = {"January": "01", "February": "02", "March": "03", "April": "04", "May": "05", "June": "06", "July": "07",
"August": "08", "September": "09", "October": "10", "November": "11", "December": "12"}

div = date.split(" ")

if len(div) == 1:
spl = date.split("/")
print(spl[1] + "/" + spl[0] + "/" + spl[2])
else:
div = date.split(" ")
div1 = div[1].split(",")
for i in dict:
if div[0] == i:
print(div1[0]+"/"+dict[i]+"/"+div1[1])

Answer 16

d= input()
x= d[0].isalpha()
if x==True:
dic={"January":1,
"February":2,
"March":3,
"April":4,
"May":5,
"June":6,
"July":7,
"August":8,
"September":9,
"October":10,
"November":11,
"December":12
}
d=d.split(", ")
d1= d[0].split(" ")
print(d1[1]+"/"+str(dic.get(d1[0]))+"/"+d[1])

else:
date=d.split("/")
print(date[1]+"/"+date[0]+"/"+date[2])

Answer 17

months = {
"January" : 1,
"February" : 2,
"March" : 3,
"April" : 4,
"May" : 5,
"June" : 6,
"July" : 7,
"August" : 8,
"September" : 9,
"October" : 10,
"November" : 11,
"December" : 12
}

date_EU = input() #MM/DD/YYYY

if date_EU[0].isalpha():
EU_list = date_EU.split(" ")
month = months[EU_list[0]]
date = EU_list[1].strip(",")
date_US = f"{date}/{month}/{EU_list[-1]}" #DD/MM/YYYY
print(date_US)

else:

EU_list = date_EU.split("/")
EU_list[0], EU_list[1] = EU_list[1], EU_list[0]
date_US = "/".join(EU_list) #DD/MM/YYYY
print(date_US)

#Here "/" is used to check if the user input has Alphabetical month name or number.

# and convered the input into list and then swap the value if month and day if it in numeric format AND so if the month is alphabet using dictionary and "f-string".

Answer 18

I have done it differently and the code passes all cases except for case 4 which is hidden and doesn't show what's wrong with the code. Please take a look and help me correct my mistake. The link to code is below.

https://code.sololearn.com/cWPzkk3iMusT/?ref=app

Answer 19

John Wells Oh, I didn't see that. Thanks a lot. I'll go and fix it.

Answer 20

John Wells I have fixed the mistakes and updated the code but it still can't pass the case 4. I've tried various date combinations and all seem to get converted properly. I can't see what I'm missing here. Show me the way please.

https://code.sololearn.com/cWPzkk3iMusT/?ref=app