Write a program in c to enter 20 number in an array. Determine the sum of odd numbers and even numbers separately

Answer 1

If you think of it a little bit, then you'll get it!

Answer 2

#include <stdio.h>
main(){
int ar[]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20};
int even=0,odd=0;

for(int i=0;i<20;i++){
if(ar[i]%2==0)
even+=ar[i];
else
odd+=ar[i];
}

printf("sum of even numbers=%d\n",even);
printf("sum of odd numbers=%d",odd);
}

Answer 3

thanks

Answer 4

This problem is similar to finding the sum of all odd and even numbers between 1 to using for loop.
Here is the sample C program to find sum of all even numbers

for(counter = 1; counter <= N; counter++) {
/* Even numbers are divisible by 2 */
if(counter%2 == 0) {
/* counter is even, add it to sum */
sum = sum + counter;
}
}

Source : http://www.techcrashcourse.com/2015/11/c-program-to-find-sum-of-even-numbers-from-1-to-N.html

Here is the sample C program to find sum of all odd numbers

for(counter = 1; counter <= N; counter++) {
/* Odd numbers are not divisible by 2 */
if(counter%2 == 1) {
/* counter is odd, add it to sum */
sum = sum + counter;
}
}

Source : http://www.techcrashcourse.com/2015/11/c-program-to-find-sum-of-odd-numbers-from-1-to-N.html