better idea? handling lists

Question

i have 2 lists, with same length: a=[1,2,3] , b=[5,7,9]
and i want output like this: c=[1+5, 2+7, 3+9], equal to [6,9,12]

my best method is:
c=[a[i]+b[i] for i in range(len(a))]

but there should be better answer

thanks for your attention

Answer 1

c = [x+y for x, y in zip(a, b)]

Answer 2

#Also this works:
c = list(map(lambda x, y: x + y, a, b))

Answer 3

And if you have lists of lists ,you can add them like this

lists_of_lists = [[1, 2, 3], [4, 5, 6]]

print(sum(x) for x in zip(*lists_of_lists)

#prints [5,7,9]

Answer 4

I think answer of both HonFu and Seb TheS are good

Answer 5

there's a better solution:
import numpy as np

numpy arrays are vastly superior in terms of performance and handling when it comes to arithmetic operations.

https://docs.scipy.org/doc/numpy/reference/generated/numpy.add.html

Answer 6

This works perfectly and is simpler than zip
c = list(map(lambda x, y: x + y, a, b))