Help me for security code coach

Question

while(s[i]!='\0')
{
if(s[i]="T")
{
break;
}
i++;
}
if(s[i-1]=='

Answer 1

#include <stdio.h>
#include<string.h>
int main() {

char inp[30],alarm[10]="ALARM";
int len,thief,check=0,test,i;
scanf("%s",inp);
len = strlen(inp);
for(i=0;i<len;i++) {
if(inp[i]=='T') {
//printf("i=%d",i);
if(i>len) {
i=0;
}
thief=i;
test=thief+1;
while(thief!=test) {
if(inp[test]=='#x27;) {
check=2;
break;
};
if(inp[test]=='G') {
check = 1;
break;
};
test++;
if(test>len) {
test=1;
}
}
};
};
//printf("i=%d",test);
if(check==2) {
printf("%s",alarm);
}
else {
printf("quiet");
};
return 0;
}

Test case 5 fails..Guide me please

Answer 2

Jayakrishna
https://code.sololearn.com/cYCXr5GaId7W/?ref=app

Answer 3

//check my code😄
#include <stdio.h>
#include <string.h>

int main() {
char c,s[100];
int i=0;

while(scanf("%c",&c)!=EOF)
if(c=='G' || c=='#x27; || c=='T')
s[i++]=c;
s[i]='\0';

printf((strstr(s,"$T") || strstr(s,"Tquot;)) ?
"ALARM":"quiet");

return 0;
}
#here is the python code

s = input()
m, t = s.find("quot;), s.find("T")
x = s[t:m] if m > t else s[m:t]
print("quiet" if "G" in x else "ALARM")

Answer 4

Check out 👇

#include <stdio.h>
#include <string.h>

int main() {
char a[50];
scanf("%[^/n]%*c",&a);
char* b[4]={'T','#x27;,'G'};
int i,f,count=0;
f=strlen(a);
for(i=0;i<f;i++)
{
if(a[i]==b[0])
{
count++;
}
else if(a[i]==b[1])
{
count++;
}
else if(a[i]==b[2])
{
count=0;
}
if (count>1)
break;
}
if(count>1)
printf("ALARM");
else
printf("quiet");
return 0;
}

Answer 5

Jayakrishna it is failing case 4

Answer 6

Jayakrishna ok

Answer 7

XxxTxx$xxG
In this case, your program not alarms...
Because s[i] = T matched but s[i-1] or s[i+1] not $, but requirement is to print Alarm..

For this simple idea is..
Just read string 1 by 1, and if any of $, T, G (gaurd) matches, give that the index value.
Then if lt;G<T or T<G<$ then display quiet else Alarm...
Hoping it helps....

Answer 8

Nishchit Rao
Your program failing the test case for xxG$XxT
Look for that...

Answer 9

Can you show your full code? Or else just try to implement as I mentioned way.. It take only 4 or 5 simple steps...

Answer 10

By this code, it raises Alarm only for cases
XxxT$xxx
or xxx$Txxx will alarm..
Not for others...
This need a lot of changes by this way.. That need loop through back and front for next $ to match..
And also if match, it does not counting for guard whether he is in between or not...
How you need to change this?

Answer 11

Try again for this...
And if don't get it, then post here again..
Good luck...

Answer 12

#include <iostream>
#include <string>
using namespace std;

int main() {
string inp;

getline(cin, inp);

for (int i = 0; i<inp.length(); i++) {
if (inp[i]=='x') {
inp.erase(i, 1);
i--;
}
}

for (int i=0; i<inp.length(); i++) {
if (inp[i-1]=='T' || inp[i+1]=='T' && inp[i]=='#x27;) {
cout << "ALARM";
goto out;
}
}
cout << "quiet";
out:
return 0;
}