I don't understand the meaning of this sentence.

Question

Format specifiers begin with a percent sign % and are replaced by corresponding arguments after the format string.

Answer 1

哪一課的？這一課嗎？

https://www.sololearn.com/learn/C/2912/

%d 整數

%f 小數

%c char

例如：

printf("%d \n", c);
format string 指 "%d \n"
argument 指 variable c

printf("%f \n", salary);
format string 指 "%f \n"
argument 指 variable salary

在第二課，第二個 code右下方，按那個 TRY IT YOURSELF，進入 code playground, 然後Run，看output。

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Due to Sololearn Q&A forum rules, please use meaningful question name and relevant tags. For this question, the tag should be "c" and "format-specifier". The question shoud be "Format Specifier in C". Please correct your question, thanks.

Answer 2

i.e
int num1 = 1;
int num2 = 2;
printf("%d and %d", num1, num2) ;
%d is a format specifier for integers.
in the above example
first %d will be replaced by num1
second %d will be replaced by num2
output : 1 and 2
if you switch the places of num1 and num2
like :
printf("%d and %d", num2, num1) ;
output : 2 and 1
there are many format specifiers it's what specifies how a value is treated, as a char or int or float...

Answer 3

%d,%s,%f like that are position holder's