Error

Question

double x=5,y=2;
Int result;
result=x%y;
cout<< result;
Why it gives error.. please explain

Answer 1

You can use % only for int datatype
for double use fmod(x,y) function from <cmath>
change result=fmod(x,y)

Answer 2

Raj Vinus why are you using double on x and y just use int and change Int to int on result
https://code.sololearn.com/cIN6wnynW4bc/?ref=app
https://code.sololearn.com/cjVbLd6t0MBb/?ref=app

The double is a fundamental data type built into the compiler and used to define numeric variables holding numbers with decimal points. 

Answer 3

The double is a fundamental data type built into the compiler and used to define numeric variables holding numbers with decimal points. 

Neither x nor y in your code reflect a decimal being used nor does result.

Answer 4

lower case int result;
and you cannot apply % operaror to double.

Edit: % is the modulus operator ie returns the reminder in integer divison

Answer 5

That was not the problem of lower case. It says invalid operands of types 'double' and 'double' to binary 'operator%'

Answer 6

BroFar I just wanted to know why we can't use double.