Halloween candy

Question

import java.util.Scanner;
import java.lang.*;

public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int houses = input.nextInt();
double x = (2/houses);
double r = x*100;
System.out.println(Math.ceil(r));
//your code goes here

}
}

Answer 1

Do Math.round after Math.ceil

like Math.round(Math.ceil(r));

Answer 2

You need to round of to the nearest integer.
Use the Math.round function in the last to get the value and then print it

Answer 3

What's wrong with it?

Answer 4

Since houses in int value and 2 is also int, then it always int value.
Result always 0 when houses >2,
So, check ones, In any case, round, or ceil or without any, r value don't get modified, in your program...

Use x= 2.0 /house.
And also convert final result to int in outputting..
By (int) Math.ceil(r)

Answer 5

You can simply cast to int when doing Math.ceil