Why does this IF statement come out as 3 and not 7?

Question

What is the output of this code?
num = 7
if num > 3:
print("3")
if num < 5:
print("5")
if num ==7:
print("7")

If I am understanding correctly, when you type in 7==7 ict omes out as true but the answer was 3? Is it going in order of what is true first or something?

Answer 1

Only 3 ,
You are right but code syntax is wrong
num = 7
if num > 3:
print("3")
if num < 5:#under first if body
print("5")
if num ==7:#under 2nd if body and second if is wrong
print("7")

Correct code is :

num = 7
if num > 3:
print("3")
if num < 5:
print("5")
if num ==7:
print("7")

Answer 2

7 is greater than 3 so 3 get printed then it moves to 7 is less than 5 which is false, since the next statement is inside the num < 5 part it get out without going further, it only will check num ==7 if num is < 7

Answer 3

If statement is like any other code.
Statement:

if num == 7:
...

was not ran because it was nested in:

if num < 5:
...

which was false.

Answer 4

ah okay, thanks everyone so it was executing it from top to bottom. Makes sense. Thank you !