Am I right? for (i=5; i>=1; i--)

Question

#include <iostream>
using namespace std;
int main(int argc, char *argv[])
{
int i, j=1;
for (i=5; i>=1; i--)
j *= i;
cout << j;
return 0;
}

1st interaction
j*=i == j= j*5 so j=5
2nd
j = 5*4 so j=20
3rd
j = 20*3 so j=60
4th
j = 60*2 so j=120
5th
j = 120*1 so j=120

Output is 120

Answer 1

Yes, you're getting it right Sh.A.kH. 👍

If you want to see what happens in each iteration then you can add `cout << j << endl;` inside the loop body. That way each change to <j> will be printed. Don't forget to wrap the loop body block with curly brackets {...}

Answer 2

//There is editor in codes Tab where you can run and check.

Answer 3

I know about the editor, but do I understand interactions right?

Answer 4

Ipang
Wow, thank you! This is the best answer cause sometimes I don't understand outputs but your way can really help me. Thanks !!!!

Answer 5

You are welcome Sh.A.kH. 👌