Iterating in two consecutive elements that will both return True on a list using "if" statement if the first one is already True

Question

x = "12helloworld34"
y = list(x)
z= ["1","2","3","4","5","6","7","8","9","0"]
for obj in y:
if obj in z:
y.remove(obj)
w = "".join(y)
print(w)

"""
output = 2helloworld4
my desired output is "helloworld".
I guess my problem is in line 5.
When it iterates to the first element on
the list and satisfy the if statement(True),
it disregard the second element which also
satisfies the if statement.
But im still not sure if that really is the
problem.
Hope you can share some insights. TIA
"""

Answer 1

Yves Manalo you are iterating over the original list so when you remove the fist element of the list, the second element become the first element but the loop counter must read the second element of the loop so that's why it skips "2"

FIX
You can iterate over a copy of list(like rodwynnejones said)
Or
You can also create one copy explisitly like this👇

https://code.sololearn.com/cTP8q9Yf7ttz/?ref=app

Answer 2

x = "12helloworld34"
y = list(x)
z= ["1","2","3","4","5","6","7","8","9","0"]
for obj in y[:]: # <--- do this, iterate over a copy
if obj in z:
y.remove(obj)
w = "".join(y)
print(w)

Answer 3

My solutions
https://code.sololearn.com/cPED5QL1hem0/?ref=app