My solution to "That's odd" doesn't work, and I dont'understand why. The #4 case remains always wrong.[SOLVED]

Question

#include <iostream>
using namespace std;

int main() {
int N, *p, i, out=0;

cin >> N;//how many numbers?
if(N<=0)
return (-1);

p = (int *)malloc(sizeof(int));
for(i=0;i<N;i++)
{
cin>>p[i];

if(p[i]%2==0)
out+=p[i];
}

cout << out;
return 0;
}

Answer 1

Resolved. I forgot to multiply the memory in the pointer to N. I had to do:
p = (int *)malloc(N*sizeof(int));

Answer 2

p[i] % 2 == 0 -> here you check if a number is even (divisible by 2)

But you need to add odd numbers.
p[i] % 2 != 0 or p[i] % 2 == 1