Operator Precedence

Question

What is the result of this code?
x = 4
y = 2
if not 1 + 1 == y or x == 4 and 7 == 8:
print("Yes")
elif x > y:
print("No")

Answer 1

Precedence for if statement is in the following order
+ == not and or
1+1 is done first, then all == in left to right order. So now you have
not true or true and false
then the boolean not is applied
false or true and false
then the and comparison is done
false or false
then the or comparison is done
resulting in false
Then the elif is done. Resulting in true and "No" is output.

Answer 2

No is answer as

In if case and is firstly processed which results in 0 then or is processed not 2==y or x==1 this also results in 0 , so it goes for elif which results No.

Answer 3

M∆π∆$
This sounds like a homework question which could have been resolved by running the code yourself.
Or are you looking for the logic behind the result?

Answer 4

Well,I guess I was just a little confused about operator precedence.Thanks for helping me out

Answer 5

No