Why this code is showing error can you explain?

Question

https://code.sololearn.com/csRr87MmaGtk/?ref=app

Answer 1

Payal Sharma , you didn't declare the base case in the recursion, so the function is called infinitely. Look at the correct code.
https://code.sololearn.com/cg17G7G9yY1F/?ref=app

Answer 2

You need stop condition in recursive method
Like
if x==1:
return 1

Answer 3

You have written the code in such a way that the recursion keeps going deeper until it runs out of depth, (processing power, time, etc)

You could do this to get a result

def factorial(x):
return x * (x-1)

print(factorial(5))

But I don't think this was your objective.
The main problem was there was no way to stop the recursive loop

Answer 4

Justus , in fact it's needed, because 0! = 1. If you call the function with 0 as argument, again it will run infinitely and will not calculate this specific case.

Answer 5

TheWh¡teCat 🇧🇬 the first condition was ok (if x==1) to exit the loop. x==0 isn't required

Answer 6

TheWh¡teCat 🇧🇬 oh. I didn't check that

Answer 7

def factorial(x):
if x == 1:
return x
else:
return x*factorial(x-1)

print(factorial(5))

Answer 8

you just missed one condition

Answer 9

you are missing the base condition of the recursive method
if x==1:
return 1

Answer 10

Just type like this :

def factorial(x):
return x*x-1

print(factorial(5))