Trouble with function like definitions

Question

#include <stdio.h>
#define func(x) x*x

int main() {
printf("%d",func(4-1));
return 0;
}
//Here I got output as -1

#include <stdio.h>
#define func(x) (x)*(x)

int main() {
printf("%d",func(4-1));
return 0;
}
//Here I got output as 9

I thought both code were same but they are not. There is something I can't understand with these lines

#define func(x) x*x
#define func(x) (x)*(x)

Can someone help me with this..

Answer 1

Yes , it works like this
1st one
4-1*4-1= -1
and 2nd one
(4-1)*(4-1)=9 because of (x)*(x)