Output of this fragment of code. Explain the the output how it works , what could be answer.

Question

int i=0;
for(;i<=5;i+=4);
{i=i*i;}
printf("%d",i);

Answer 1

i<=5
i first equals 0 so for loop is entered
i = 0 * 0
i += 4
i now equals 4, still less than 5 loop again
i = 4 * 4
i equals 16
I += 4, i now equals 20, greater than 5 loop exits

printf("%d", i) output value of i 20

Answer 2

Thank you , i was looking for this thing.

Answer 3

It is producing output as 20,,,, how????

Answer 4

That code won't compile, it has a few errors.
1 semicolon after closing parentheses of for statement.
2 lack of semicolon after last i in code block
3 improper use of print %
See code below

#include <stdio.h>

int main() {
int i=0;
for(;i<=5;i+=4) {
i=i*i;
}
printf("%d",i);
return 0;
}