Please anyone help me with this code.

Question

I want space between each number in output

n=int(input())
list1=input()
length=len(list1)
if length == n :
print(list1[::-1])
>>>Input (stdin)
5
12345
Your Output (stdout)
54321>>>

Answer 1

print(*list[::-1])

Using this you will get your desired output..

just make this change(as mentioned above)in your code

HOPE IT HELPS!!!☺️

Answer 2

Ramya Thiurmalisamy

* symbol is use to print the list elements in a single line with space and in strings as well

Answer 3

Ok, then do one thing, create an empty string outside loop(for eg. x) and then do this -

for i in list1[::-1]:
x += i + " "

print(x)

Answer 4

you can use this code
For i in list1[::-1]:
X+=I+" "
Print (x)

Answer 5

n=int(input())
list1=input()
length=len(list1)
If length==n
For i in list1:
Print(i," ")

Answer 6

Simply take every input as string eventhough it's a number... Or else use the logic of reverse of a number...(not exact logic, modify the code and use)

Answer 7

What I am saying is -
After the if statement,

for i in list1[::-1]:
print(i + " ")

Answer 8

This is it.

list=[12345]
rev=list[::-1]
print (rsd, sep=' ')

To print in new lines, a loop is best.

Answer 9

Add a for loop in it printing each element + " "(space)..

Answer 10

RAJESH SAHU yeah!!! It's work.but can you explain how it is?

Answer 11

Varun Vaswani can you explain how I can use for loop here?I can't able to understand what you say!!

Answer 12

Varun Vaswani but it givese a output in newlines not in a same line.😑😑🤔

Answer 13

@ Varun Vaswani ok I will check it out.Tq

Answer 14

Welcome

Answer 15

@yeah!!!it's working 👍👍🤝🤝🙏🤩🙏✨💫

Answer 16

Varun Vaswani it'll also print space at the end which we won't need...!!