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Sort an array.

I can’t come up with an algorithm. The right element should be equal to the left of the next. Input: {0,0}, {0,3}, {1,6}, {2,1}, {3,2}, {3,6}, {6,0}. Output: {3,6}, {6,0}, {0,0}, {0,3}, {3,2}, {2,1}, {1,6}.

23rd Apr 2020, 11:40 AM
Chowa
Chowa - avatar
3 odpowiedzi
+ 2
Hello Chowa Looks like domino stones. ;) I would say you will need a bracktracking algorithm. You start with a stone and try to add another stone. Until you find a solution. If you can't find a stone, you remove the last stone. And try another one. If you have to remove the first stone, but it's also your last stone -> no solution Example: {0,0} {0,3} {3,2} {2,1} {1,6} {6,0} remove {6,0}, {1,6}, {2,1}, {3,2} {0,0} {0,3} {3,6} {6,0} remove all stones, start with another one. {0,3} {3,2} {2,1} {1,6} {6,0} {0,0} remove all stones until {0,3} {0,3} {3,6} {6,0} {0,0} remove all stones {1,6} {6,0} {0,0} {0,3} {3,2} {2,1} remove {2,1} and {3,2} {1,6} {6,0} {0,0} {0,3} {3,6} remove all stones until {6,0} {1,6} {6,0} {0,3} {3,2} {2,1} and so on...until you start with {3,6} then you will find the solution.
23rd Apr 2020, 12:56 PM
Denise Roßberg
Denise Roßberg - avatar
+ 2
And of course you can improve it: For example a stone start with a number which does not fit: This stone has to be the first stone. End if a stone ends with a number which does not fit: This stone has to be the last stone. About backtracking: https://www.google.de/amp/s/www.freecodecamp.org/news/backtracking-algorithms-recursive-search/amp/
23rd Apr 2020, 1:03 PM
Denise Roßberg
Denise Roßberg - avatar
+ 1
Many thanks!
23rd Apr 2020, 1:06 PM
Chowa
Chowa - avatar