Plz explain this code

Question

#include <stdio.h>
int main()
{
int arr[]={1,2,3,4,5};
int *p=arr;
++*p;
p+=2;
printf("%d",*p);
return 0;
}

Answer 1

Here ,
1.) arr[]={1,2,3,4,5};
is creating an array of size 5 and arr stores the base address of first element as know array allocates memory in contiguous locations.

2.) int *p=arr;
assigns the base address to pointer 'p' where pointer is variable which can store address of other element.

3.) ++*p;
does the value incrementation of p pointing address
Here according to precedence of operators '*' operator comes first then ++ operator here therefore it increments value at address stored.

4.) As told earlier , p holds the address of arr so as 'p' is storing address p+=2; increments address by 2 i.e it goes to element 3 in array as elements are stored in continuous manner.

5.) Finally printf("%d",*p);
Prints value of *p i.e , 3

I hope this helps you Kawser . If you are still not clear please ask me.Thank you.