+ 1
Operator Precedence
I don't understand this concept: >>> False == False or True True >>> False == (False or True) False >>> (False == False) or True True
2 odpowiedzi
+ 2
Everything that is in parenthesis"()" is operated first as it have highest precedence. Rest is performed from left to right.
1) False == False or True
True or True (as False == False is true)
>>>>True
2) False == (False or True)
False == (True)
>>>>False
3) (False == False) or True
True or True
>>>>True
+ 2
What you didn't understand? In 1st == has higher precedence ,so that's why it evaluates to True ,in rest bracket ones are evaluated first