Python program to find sum of all even numbers in a list of numbers. Can’t find what I did wrong ;-;

Question

#The program asks to input first the number of values u will .be adding and then the numbers that ur inputting

N = int(input())
List = []
sum = 0
while N > 0:
List.append(int(input()))
N -= 1

for num in List:
if num % 2 == 0:
sum = num + sum
print (sum)
else:
print (0)

This should work, but it isn’t working idk why. I’ve been stuck at finding what went wrong for a day can anyone help me.

Answer 1

Try this

N = int(input())
List = []
list = []
while N > 0:
List.append(int(input()))
N -= 1

for num in List:
if num % 2 == 0:
list.append(num)
else:
pass
print(sum(list))

Fixed !

Answer 2

Thanks 🇮🇳 AYUSH.ks 🇮🇳 and Manu_1-9-8-5 .

Answer 3

🇮🇳 AYUSH.ks 🇮🇳 can we use continue instead of pass.

Answer 4

Yes Rithea Sreng you are true . A single task can be written in various way . But the main thing is that to reply the answer in the format in which a asker is asking

Answer 5

AYUSH.ks, if you use sum ( as identifier) and sum() function in a code it will bring up a TypeError. The reason of this is, that by using sum as an identifier name you overwrite parts of the sum() object. You can check this with this code: ( run either first or second part of the code separately)

my_sum = 4 +3
lst = [1,2,3]
total = sum(lst) # NO error

sum = 4 +3
lst = [1,2,3]
total = sum(lst) # TypeError: 'int' object is not callable

Answer 6

Hay Intenzi its edited

Answer 7

Or try this

N = int(input())
List = []
sum = 0
while N > 0:
List.append(int(input()))
N -= 1

for num in List:
if num % 2 == 0:
sum = sum + num
else:
pass
print(sum)

Answer 8

I only wanted to give a very general remark: Do not use identifier names (e.g. for variables) that are identical with python keywords or buil-in functions. So "sum" should not been used, becuase this name is used for a function. If you do it anyway, it can have unexpected consequences. You can use like "sum_" instead.

Answer 9

🇮🇳 AYUSH.ks 🇮🇳 ty its perfect, to confirm the pass is used when u dont want anything in the else parameter?

Answer 10

Yes Lothar aggred but if we force python to so then it will obviously do . Because sum() and sum are not same . one is a variable and another is function.

Answer 11

Yes Intenzi you got it

Answer 12

What exactly is not like you expected it?

I entered 3 for N, then 2, 5, 6 and got:
2
0
8

Answer 13

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 I dont understand exactly how that code worked in a single line but thats awesome!

Answer 14

n=int(input())
a=[]
for j in range(n):
m=int(input())
a.append(m)
sum=0
for i in range(n):
if (a[i])%2==0:
sum=sum+a[i]
else:
sum=sum+0
print(sum)

Try this this will work correctly

Answer 15

N = int(input())
List = []
sum = 0
while N > 0:
List.append(int(input()))
N -= 1

for num in List:
if num % 2 == 0:
sum = num + sum
#so don't print the sum at a time
else:
#to ignore odd numbers
continue
#print the sum out of loop
print(sum)

Answer 16

Puthur Harthik or you just remove the else-block as it is useless like this when we have no follow up code.

Answer 17

This should give you what you are looking for:

list = [1,2,3,4,5,6,7,8,11,10]
sum = 0
for i in list:
if i%2 ==0:
sum += i
print (sum)

Answer 18

I wish for it to output only the final sum...

Answer 19

you need to remove the else statement and the print(sum) must be after for statement

Answer 20

By the way, you can do it all in one loop and you don’t need the list