why output is 3 why why why

Question

// why output is 3 why why why ???

#include <stdio.h>
#define square(r) (r*r)
int main()
{
int y = 1;
printf("Area is %d\n", square(y+1));
return 0;
}

Answer 1

The macro is : square(1) (1+1*1+1)
So according to operator precedence, multiplication has higher precedence than addition.
So first 1*1 is evaluated then addition is done.
So 1+(1*1)+1 = 1+1+1 = 3

Answer 2

Thanks nova

Answer 3

It will be calculate like this square(1) (1+1*1+1)

So 1+(1*1)+1 = 1+1+1 = 3