JavaScript

Question

Fill in the blanks to declare an arrow function that takes an array and prints the odd elements.

const printOdds = (arr)__{
__.forEach( __ => {
    if (el % 2 != 0) console.log(el);
  });
}

Answer 1

omkar bawankar

:
arr
el

but go through course again.

Answer 2

If you don't have any question than please don't ask us to do what needs to be done by you ,if you didn't understand you can go through the course again

Answer 3

I need answer

Answer 4

const printOdds = (arr) => {
arr.forEach((el) => {
if (el % 2 != 0) console.log(el);
});
}

// or:

const printOdds = arr => {
arr.forEach(el => {
if (el % 2 != 0) console.log(el);
});
}

/*
* because round brackets are not required, if any argument.
* This is wrong:
* const a = => 5
*/

Answer 5

=>
arr
el

This is very correct!