How to print a hollow rectangle pattern with numbers using FOR loop? (Or any other loop)

Question

/*The pattern should be like this*/
1 2 3 4 5
16 6
15 7
14 8
13 12 11 10 9

Answer 1

# static version

pat = []
for i in range(5):
pat.append([' ']*5)
j = 4
k = 4

for i in range(16):
s = str(i+1)
if i < 9:
s = ' ' + s
if i < 5:
pat[0][i] = s
elif i < 9:
pat[i-4][4] = s
elif i < 13:
j = j - 1
pat[4][j] = s
else:
k = k - 1
pat[k][0] = s

for i in range(len(pat)):
pat[i] = ' '.join(pat[i])
pat = '\n'.join(pat)

print(pat)

# parametric version

def get_pat(w,h=None):
if h is None:
h = w
j = w - 1
k = h - 1
sz = ( j + k ) * 2
sp = ' ' * len(str(sz))
pat = []
for i in range(h):
pat.append([sp]*w)

for i in range(sz):
s = str(i+1)
n = len(str(sz)) - len(s)
if n != 0:
s = ' ' * n + s
if i < w:
pat[0][i] = s
elif i < w + h - 1:
pat[i-j][j] = s
elif i < 2 * w + h - 2:
j = j - 1
pat[k][j] = s
else:
k = k - 1
pat[k][0] = s
for i in range(len(pat)):
pat[i] = ' '.join(pat[i])
return '\n'.join(pat)

print()
print(get_pat(5))
print()
print(get_pat(15,8))

# it seems that code playground trims outputs, so you can fix it by prepending a character different from a space at each line: replace the last join() call ( return statement in parametric version, and final assignement of 'pat' in static one ) with:
# '.'+'\n.'.join(pat)

Answer 2

/*You can write code in any programming language you love*/

Answer 3

I want logic.

Answer 4

Use print, what's the problem?