s1 =[3,4] s2 =[1,2] s3=list() i=0 j=0 for i in s1: for j in s2: s3.append((i,j))

Question

Explain above step by step

Answer 1

s1 =[3,4]
s2 =[1,2]
s3=list()
i=0
j=0
for i in s1:
for j in s2:
s3.append((i,j))
i=i+1
j=j+1
print(s3)
_____________________________________
Explanation:

# don't mind i=0, j=0
# in line 6 and 7,
_______________
|for i in [3,4]: |
| for j in [1,2]: |
------------------------
|
---------------------------------------------------------------
# let i = 3:
if j = 1
s3.append((3,1)) => s3 = [(3,1)]

i = i + 1 => i = 3+1 => i = 4

if j = 2
s3.append((4,2)) => s3 = [(3,1), (4,2)]
----------------------------------------------------------------
# let i = 4:
if j = 1
s3.append((4,1)) => s3 = [(3,1), (4,2), (4,1)]

i = i + 1 => i = 4+1 => i = 5

if j = 2
s3.append((5,2)) => s3 = [(3,1), (4,2), (4,1), (5,2)]
------------------------------------------------------------------------------
then output is [(3,1), (4,2), (4,1), (5,2)]

Answer 2

First outer loop runs one time with i=3
Second inner Loop runs two times and appends (3,1) and (3,2) to s3 list ,
Now first outer loop runs second time with i=4
Second inner Loop runs two times again and appends (4,1) and (4,2) to s3 list

s3 now contains =[(3,1),(3,2),(4,1),(4,2)]

hopefully you understood what I wrote ,
In short inner Loop executes fully and after then control is thrown back to outer loop which runs one time again and then inner Loop executes fully and so on

Answer 3

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 Yup thanks😄

Answer 4

SAADAT ALI look at the question ,you skipped not us

Answer 5

I know you would ask. j = j + 1 is not necessary because after appending (i, j) in s3. j = j+1 as no use.
For example,
if i=3, j=1
i = i + 1 => i = 3+1 = 4
j = j + 1 => j = 1+1 = 2
In 2nd for loop i.e. for j in s2
j changes its value to 2 but i is not changed
So j = j +1 is not necessary

Answer 6

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 why do you mention people name first , instead take time to write whole explanation and then comment ,

Answer 7

Yup after tagging his name you edited it lol

Answer 8

I can't take screenshot of output otherwise that would be a proof that answer is according to my explanation

Answer 9

Thanx now understand

Answer 10

[(3,1),(3,2),(4,1),(4,2)]

Answer 11

I m new and confused in nested for loops

Answer 12

uhh I am only a mighty web developer

Answer 13

Ok

Answer 14

It is c++

Answer 15

Nc

Answer 16

It is pyrhon 3.7

Answer 17

Ye

Answer 18

Yes

Answer 19

Thanx my account is no activated

Answer 20

Its give out put [(3,1),(4,2),(4,1),5,2)]