Explain me the answer

Question

What is the output of this code?
int [] b = {5, 6, 3, 8, 7}
int sum = 0;
for (int i = 0; i < 5; i ++) {
if (i % 2 == 0);
sum += b[i];
}
System.out.print(sum);

Answer: 15

Answer 1

When i = 0, 0 % 2 == 0, b[i] = b[0] = 5
When i = 2, 2 % 2 == 0, b[i] = b[2] = 3
When i = 4, 4 % 2 == 0, b[i] = b[4] = 7

Finally 5 + 3 + 7 = 15

Answer 2

If i%2==0 means if 0,1,2,3,4 divided by 2 results in remainder 0 add the value at the i index of array b to the variable sum
so first
0%2 is equal to 0 ,so Loop starts again

And same for 2%2 ,4%2 results in 0

So the value at index 2 and 4 also get added to sum
sum+=b[i]

it's like
sum+=b[0]
sum=sum+b[0]
sum=0+5
sum=5

Again

sum+=b[2]
sum=sum+b[2]
sum=5+3
sum=8

Again

sum+=b[4]
sum=sum+b[4]
sum=8+7
sum=15

Answer 3

Терещенко Дмитрий
The code will be

public class array{
public static void main(String args[])
{
int [] b = {5, 6, 3, 8, 7}
int sum = 0;
for (int i = 0; i < 5; i ++) {
if (i % 2 == 0){
continue;
}
sum += b[i];

}
System.out.print(sum);
}
}

The logic here is if the i th elementof the array is an even number then it skips the current iteration and proceeds to next but if it is a odd number it adds it to sum variable.

So output=5+3+7=15