+ 1
Area of triangle is ZERO! (This is a question from challenge). The output is different in both cases below. What's the reason?TY
//CASE - 1 #include <iostream> using namespace std; int main() { float area, base = 5, height = 10; area = (1/2)*base*height; cout<< area; return 0; } // Output = 0 // CASE - 2 #include <iostream> using namespace std; int main() { float area, base = 5, height = 10; area = (0.5)*base*height; cout<< area; return 0; } // Output = 25
2 odpowiedzi
+ 6
In the first case, (1/2) is treated as integer division, with 0.5 getting truncated to 0, which in turn turns the entire product into zero. Writing 1 as 1.0 would easily solve that problem.
+ 3
Stellar Fox , ~ swim ~
I was thinking like this ↓
(1/2) = 0.5 it's a double so it will be used in operation without removing "5".
But I get it now. An integral fraction will not be treated the same as a float type fractional value.
(And being in the middle of a calculation won't save those integer numbers from being attacked by double! 😈)
Thank you two!