Could explain how this code gets executed line by line, I get confused with with it!!!

Question

def smart_divide(func):
def inner(a,b):
print("I am going to divide",a,"and",b)
if b == 0:
print("Whoops! cannot divide")
return

return func(a,b)
return inner

@smart_divide
def divide(a,b):
return a/b

Answer 1

First you define a function smart_divide. Inside it, you declare another function inner which is only accessible from inside smart_divide.

Important thing to note is, the smart_divide function takes a function as parameter (func). The func variable can then be accessed by the inner function.

Then, you declare some functionality for the function inner. That is, if parameter b == 0, you return None from the function. Else, you execute the func parameter taken in as an argument by the smart_divide function.

Then you declare a function divide. The line
"@smart_divide" Literally does this -

divide = smart_divide(divide)

So now when you call divide with arguements, you are actually calling the inner function, because smart_divide returns inner.

I don't know how well I explained it. So this is a link to an excellent tutorial
https://realpython.com/primer-on-JUMP_LINK__&&__python__&&__JUMP_LINK-decorators/