Output of this confused me(I don't know diffrences between line2, 4 and 6)

Question

print(False == False or True)

print(False == (False or True))

print((False == False) or True)

print(2 ** 2 == 5 or 4)

print(2 ** 2 == (4 or 5))

print((2 ** 2 == 5) or 4)

print((2 ** 2 == 4) or 5)

print(2 + 2 == 4 or 5)

Answer 1

This has to do with operator precedence.
I have a reference for you here: https://www.programiz.com/JUMP_LINK__&&__python__&&__JUMP_LINK-programming/precedence-associativity

Basically, the logical equals operator has higher precedence than the "or" keyword, and at the same time lower precedence than the usual exponentiation or sum operators.

Therefore, "False == False or True" is the same as "(False == False) or True".
For "2 ** 2 == 5 or 4", an equivalent expression would be "((2 ** 2) == 5) or 4".
Same with "2 + 2 == 4 or 5": "((2 + 2) == 4) or 5".

You can alter the way an expression is evaluated by using explicit parentheses.

Line 2: "False == (False or True)"
* First, "False or True" is evaluated, which is "True".
* Second, we get "False == True", which is "False".

Lines 4 and 6 are equivalent to "((2 ** 2) == 5) or 4":
* First, "2 ** 2" is "4".
* Second, "4 == 5" evaluates to "False".
* Third, "False or 4" evaluates to "4" as the "4" is a "truthy" value. (Not "True" but in a way, being an integer makes the "or" behave as an OR operation between integers; see here to check the values "True" and "False" convert to when used with integers: https://stackoverflow.com/a/2764099 )