C language pattern solving 1 2 0 2 3 0 0 0 3 4 0 0 0 0 0 4 5 0 0 0 0 0 0 0 5

Question

#include <stdio.h>

int main() {
int i,j,k;
for( i=1;i<=5;i++)
k=i;
{
for(j=1;j<=9;j++)
{
if(j>=6-i&&j<=4+i)
{
if(j==6-i&&j==4+i)
{ printf("%d",k);
k++;}

else
printf("0");

} else
{
printf(" ");
}
}
printf("\n");
}
return 0;
}

Answer 1

It is not printing the above pattern ..tell me where the modification is needed

Answer 2

your program lacks mobility since it doesn't take in inputs. try understanding the codes i've written instead.

https://code.sololearn.com/cxAtdgZ6ED52/?ref=app

Answer 3

Thnx

Answer 4

Suman Singh
this code gives you correct output, have a look

for(i=0;i<=no_rows;i++)
{
for(j=0;j<=no_rows-i;j++)
printf(" ");
for(j=0;j<=i;j++)
{
if((j==0) || (j==i))
printf("%d ",i+1) ;
else
printf("0 ");
}
printf("\n");
}