Help understand this code it's just outputs 2 thing's ot error

Question

#include <iostream>
#include <string>
using namespace std;
class point
{
public:
int *data;
point(int size)
{
this->data=new int[size];
for(int i=0;i<10;i++) < what's happening here is
{ is it changing anything
what's making "for" here?
data[i]=i;
}
cout<<"constructor"<<endl;

}

~point()
{
delete[] data;
cout<<"destructor"<<endl;
}

void print(int size)
{
cout<<"func"<<*data<<this<<endl;
}

point foo()
{
point temp(1);
return temp;
}
};

int main() {
point add(1);

return 0;
}
https://code.sololearn.com/cP3ooW12leL6/?ref=app

Answer 1

You allocate <size> amount of `int` block for <data>, then you try to fill 10 blocks using a for-loop in the class constructor.

But notice this, in main function you instantiate `point` class with just 1 -> `point add(1)`. Yet again, the for-loop in constructor tries to fill up to 10 blocks. Idk, but that didn't look right to me, somehow : )

Answer 2

Thanks

Answer 3

Thanks but I know that function for bro , I'm asking how can I use it (for) in this code : )

Answer 4

Can you make some example? : )

Answer 5

I was thinking just replace the 10 in the for-loop with <size>, that way you won't be using more than what was allocated for <data>.

for(int i = 0; i < size; i++)

When you create an instance in main function, you pass 1 as constructor argument, so the constructor reserve 1 block of `int` for you. But the for-loop in constructor tries to use more (up to 10 blocks), because the for-loop condition specifies `i < 10` : )

Answer 6

(My English is not so good )
What this code need to output if I'll use all 10 blocks : )

Answer 7

Change the print function as follows:

void print(int size)
{
for(int i = 0; i < size; i++)
{
cout << data[i] << endl;
}
}

And call it in main ...

add.print(10)

That's it I guess ...