Tell me why, plz

Question

print( True or False and False)
print(( True or False) and False)
print( False and False or True)

The result is:
True
Flase
True

Answer 1

both operands of an 'and' comparison have to be True to return True
if either operand of an 'or' comparison are True the True is returned
'and' has higher operator precedence than 'or'

True or False = True
False and False = False
True or False and False = True or False = True

() has higher operator precedence than 'and', 'or'
(True or False) and False = True and False = False

False and False or True = False or True = True

Answer 2

If you have remember this in such way let True =1 ,False=0 ,and = * and or = + , so * has more precedence then + . But always solve first inside perenthesis problem then you can solve outer.
print (1+0*0)
print ((1+0)*0)
print (0*0+1)
Output 👇👇
1= true
0= false
1= true

Answer 3

According to operator precedence the and has higher precedence then or so in

Case1. False and False is equal to false because it will only return true when both will be true and then it becomes true or false . Or will return true if any one of them is true so here in true or false "true" is present so the final result is true.

Case2. Parenthesis "()" have higher precedence then "and" so (True or False) will exicuted first and will give true because one of them is true and then same process. finally true and false which will result in False

Case3. Similar to case1 only the order is changed

Answer 4

To understand the results, you have to understand logic and order of precedence / operations.

For this code, the rules to follow are:
1. Solve 'and' before 'or'.
2. Solve the inner 'bracket / parenthesis' first before the outer bracket.
3. Solve 'and' before 'or'.