how to call a function as an argument inside of the function (python)

Question

This is very hard to explain. I might as well just show what I'm trying to do.

class Player:
def __init__(self, x, y, w, h):
self.x = x
self.y = y
self.w = w
self.h = h

def keyMove(action):
action()

As you can see, I will pass a function as a parameter and call it inside the function. Let's just pretend the key functions I will use exist hypothetically. I planning to use it like this:

for event in pygame.event.get():
if event.type == UP_ARROW:
p.keyMove(upFunction())

elif event.type == DOWN_ARROW:
p.keyMove(downFunction())

To clarify, when the player clicks the up arrow, a function gets called, same for down arrow

How can I call the functions parameters inside the original function? Sorry, this was very hard to explain.

Answer 1

Last time that happened, I had forgotten the self parameter

Answer 2

The function is returning a value, right?
https://www.sololearn.com/learn/JUMP_LINK__&&__Python__&&__JUMP_LINK/2459/

I dunno

Answer 3

Maybe you could see this:

https://code.sololearn.com/ce664AekBveN/?ref=app

Answer 4

🇧🇩🇳‌🇴‌🇷‌'🇼‌🇪‌🇸‌🇹‌🇪‌🇷‌ I don't know. It comes throwing a t type error. To simplify it to something else

def thing(func):
return func()

def hi():
print("hi")

thing(hi())

that should output "hi"

Answer 5

Bagon It says: "Player object not callable"

Answer 6

Bagon I tried something else:

def moveKey(action):
return action()

p = Player()

def hi():
print("test")

p.moveKey(hi)

It gives an error:

moveKey() takes 1 positional argument but 2 were given.

How? I literally gave it 1 argument!

Answer 7

🇧🇩🇳‌🇴‌🇷‌'🇼‌🇪‌🇸‌🇹‌🇪‌🇷‌ Works! I don't know how that works! I didn't even mentioned the __init__ parameters so I wonder why it throws an error