What does array elements as counters in jave mean?

Question

Every time, when I changa the number the output also changes, though I use the same numbers?

Answer 1

Can you explain same with that code snippet..?

Answer 2

import java.util.Random;
public class apples {
public static void main(String[] args) {
Random rand = new Random();
int freq[]=new int[7];

for(int roll=1;roll<1000;roll++) {
++freq[1+rand.nextInt(6)];
}
System.out.println("Face\tFrequency");
for(int face=1;face<freq.length;face++) {
System.out.println(face+"\t"+freq[face]);
}
}
}

Answer 3

Really, I didn`t understand what is array elements as counters and in this code above if I change the number, I mean
for (int face=1;.... ) to int face=0 and then again int face=1, it outputs different numbers.

Answer 4

I really don't understanding question clearly..
Array indexes starts from 0, not 1.
So your array of length 7 integers are accessed through 0 to 6 indexes but in your code your not touching freq[0] anywhere so it's value is 0 only.
And actually changes value definatively because rand.nextInt(6) returns values randomly from 0 to 5, every time it different, you cannot predict.

If It is not clear, then specify your expected output with small range briefly..