Nested For Loops Python (Beginner Question)

Question

I have an idea of what I need to do for data extraction from the question, but I am unable to actually write the code from scratch:

Daily rainfall (measured in mm) in Brighton for first quarter of the year are stored in the following lists:

jan = [1, 3, 0, 4, 6, ...]
feb = [5, 0, 0, 2, 3, ...]
mar = [10, 31, 21, 53, 9, ...]

... represents more values not shown

The following list contains the daily rainfall for the first quarter of the year

rainfall = [jan, feb, mar]

Write a program to find
(a) for each month, the number of days where there is no rain
(b) the average rainfall for the first quarter

I barely managed (a):

for day in jan:
if day == 0:
print("Zero rainfall days in jan: ")
print(day)

for day in feb:
if day == 0:
print("Zero rainfall days in feb: ")
print(day)

for day in mar:
if day ==0:
print("Zero rainfall days in mar: ")
print(day)

How can I 'count' the number of 0's?

How can I add all index values and divide by index count for (b)?

Thank you in advance!

Answer 1

Since we shouldn't do the homework for you, I write two other examples to help you.

(1) Adding something
total=0
for i in [1,2,3]:
total=total+i
print(total) #total=1+2+3=6

(2) How many numbers are in each list
print(len(jan))

Answer 2

Thanks all! I think I solved (b)...?

jan = [1, 3, 0, 4, 6, ...]
feb = [5, 0, 0, 2, 3, ...]
mar = [10, 31, 21, 53, 9, ...]
rainfall = [jan, feb, mar]

average_rainfall = total_rainfall / total_days
total_rainfall = sum((jan)+(feb)+(mar))
total_days = len((jan)+(feb)+(mar))

print(average_rainfall)

Why doesn't this work:

average_rainfall = total_rainfall / total_days
total_rainfall = sum(rainfall)
total_days = len(rainfall)

print(average_rainfall)

?

Answer 3

codemonkey thanks, I'll take note to input my code in my future queries!