Plz help me to improve my Deja Vu code....!

Question

word=input()

j=word[i]
for j in word:
while word.count(j)==1:
i+=1
print('Unique')
else:
print('Deja Vu')

Answer 1

s=input()
t=set(s)
if len(s)==len(t):
print("Unique")
else:
print("Deja Vu")

Answer 2

~ swim ~
Thnx but I have not coverd function part yet in python. So plz give me solution using coditional statements

Answer 3

Ayush Rastogi
Thnx bro
I want code in this manner

Answer 4

s=input()
c=0
x=0
for i in range(len(s)):
ch=s[i]
for j in range(len(s)):
if s[j]==ch:
c+=1
if c>=2 :
x+=1
c=0
if x>=1:
print("Deja Vu")
else:
print("Unique")

Short and Simple.

Answer 5

You can Write down like this in easiest way!

word = input()
def deja(word):
for i in word :
if word.count(i)>1:
return 'Deja Vu'
return 'Unique'
print(deja(word))