Why does this code print out a number?

Question

#include <iostream>
using namespace std;

int main() {

char zzz = 'z';
for (int i = 0; i< 10; i++)
cout << zzz+i; // why does the line output a number?

return 0;
}

Answer 1

char zzz is implicitly converted to an int when it is added to i.
If you'd like it to output as a char you can cast it to a char.
cout << (char)zzz+i;

Answer 2

Got it.

So a character will be converted to its decimal ASCII value when it is added to either an integer or another character.